Find lim (x^2-25)/(x^3-27) x-> 3 ? Please help?? (:
ok, so what do you think we can do with this?
graph it! :p lol
When I see this equation, I think that the top looks familiar, there is an x^2 term and a 25 term, which is 5^2. I also see that it is a difference of squares, which I know how to rewrite. Do you know how to rewrite this?
no :o
Ok, so \(a^2-b^2=(a+b)(a-b)\). This is very useful to remember. What is a and b in our case?
You can read this later: http://en.wikipedia.org/wiki/Difference_of_squares We have for our case \(a=x\) and \(b=5\). Next, let's look at the denominator: It's a difference of cubes: \(\Large a^3-b^3\). There is also a formula for that. What is a and b in this case?
http://en.wikipedia.org/wiki/Difference_between_two_cubes#Sum.2Fdifference_of_two_cubes
You can read that later. We have now for this difference of cubes \(\Large x^3-3^3\), which can be written as \((x-3)(x^2+3x+9)\).
So, no you have a factored numerator and denominator. In the denominator you have a term \(x-3\). What happens as \(x\to3\)?
*now
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