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The line through the origin perpendicular to the line x-3y=9 (write an equation of the line described)
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you have f(0)=0 and you want to find the line perpendicular to x-3y=9 Note that perpendicular lines have slopes that are -1/m, if m is the slope of the original line.
thanks, I am having trouble working this out, can you help me?
write the equation for the line you're given in terms of y, so it looks like y=blah blah
(move everything by y to the right side of the equation)
this is what I got -3y=9-x
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divide both sides by -3
y=x/3-3
what is the slope?
i got 1/3
ok, so if m=1/3 what is -1/m?
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im not sure... that's what im confused on
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