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Find an equation of the tangent line to the curve at the given point. y=sin(2lnx) (1,0)
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recall that the derivative of the function will tell you the slope of the tangent line. You will need to find the derivative of the function first.
Do you know how to do this?
I got sin2/x
I don't think that's correct
wait imma try again, theres a lot on my page
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okay, I got cos(2lnx)*2/x+lnx
Diz, you were close on the last try but should not have +lnx. I'm guessing you may have been thinking you had to apply the product rule but there's no product here.
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