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Precalculus
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tan (θ − π/ 2) = 1
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\[\LARGE \tan x= \frac{\pi}{4}\] So,necessarily, \[\LARGE \frac {\pi}{4}=\theta-\frac{\pi}{2}\] can u solve for theta?
tan(theta-pi/2)=1 => theta-pi/2=pi/4 +K*pi (K can be any integer number) => theta = 3/4*pi + K*pi
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