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What are three different values that complete the expression x^2 + []x + 16 so that you can factor it into the product of two binomials?
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Factoring an equation like this requires that the last terms of the binomials add to be the middle term and multiply to be the last term, so start with the factors of 16.
Okay, so 2, 4, and 8.
The factors need to be in pairs: 2 * 8 4 * 4 Play around with positive and negatives - remember that a negative times a negative is positive. Make a few binomial factors and FOIL them to see what you get for the middle term. \((x+4)(x+4) \implies x^2 +8x+16\)
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