Question

Condense logx-logy-logz

Answer 1

Is it logx/logy/logz

Answer 2

hint : log(a) - log(b) = log(a/b)

Answer 3

Oops so log of. X over y over z

Answer 4

?

Answer 5

another hint :
logx-logy-logz = logx - (logy+logz)

Answer 6

So the question is 1/3logx-2log(x-2)-4log(y+2)

Answer 7

X+2 not minus

Answer 8

well it is different then
(1/3)logx = log(x^(1/3))
-2log(x+2) = -log((x+2)^2)
-4log(y+2) = -log((y+2)^4)

log(x^(1/3)) - log((x+2)^2) - log((y+2)^4) = log(x^(1/3)/((x+2)^2*(y+2)^4))

Answer 9

idk this