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Fans the slope of the curve at the indicated point.
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Calculate the derivative.
\[ \frac{d}{dx}|x| =\begin{cases} \frac{d}{dx}( x)& x>0\\ \frac{d}{dx} (-x)&x<0 \end{cases} =\begin{cases} 1& x>0\\ -1&x<0 \end{cases} \]You can now use chain rule.
\[ u = x-2\quad \frac{du}{dx}=1 \]Thus \[ \frac{d}{dx}|x-2| = \frac{d}{dx}|u|\cdot 1 = \begin{cases} 1 &u>0\\ -1&u<0 \end{cases}= \begin{cases} 1 &x-2>0\\ -1&x-2<0 \end{cases}= \begin{cases} 1 &x>2\\ -1&x<2 \end{cases} \]
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