Question

Integration by parts: I'm trying to identify u and dv of the following problem: 6x sinx cosx dx. Can someone show me step by step how I do this?

Answer 1

i would first simplify it by using the double angle identity
\[\sin(2x) = 2 \sin x \cos x\]
\[\rightarrow 3\int\limits x \sin(2x) dx\]
u = x .......... dv = sin(2x)
du = dx ........ v = -cos(2x)/2

Answer 2

Ok, thank you.

Answer 3

yw