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\[\sqrt{121a^2b^2}\]
\[\sqrt{abc} = \sqrt{a} \times \sqrt{b} \times \sqrt{c}\]
@jdoe0001
\(\bf\sqrt{121a^2b^2}\\ --------\\ 121 = 11^2\\ --------\\ \sqrt{121a^2b^2}\implies \sqrt{11^2a^2b^2}\)
so, that leaves you with?
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