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integrate (1+x)/x
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\[ \frac{1+x}{x} = \frac 1x + \frac xx \]
Since we're integrating, the discontinuity can be ignored so: \[ \frac 1x +\frac xx \to \frac 1x +1 \]
Welcome to Openstudy @lizebender
im solving a linear algebra problem trying to find the integrating factor e^S(1+x/x)
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coming up with x +e as the final answer, however mymathlab is not accepting that
Consider the equation x y' + (1+x) y = x (A) Find the integrating factor u(x) \displaystyle u(x) = (B) Find the general solution of the homogeneous problem y_c(x) \displaystyle y_c(x) = C (C) Find the particular solution y_p(x) \displaystyle y_p(x) =
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