I need help!
Solve for triangle ABC:

1. a = 28, b = 15,

Question

I need help!
Solve for triangle ABC:

1.	a = 28, b = 15, <A = 110˚
2.	a = 30, c = 40, <A = 37˚
3.	b = 73, c = 82, <B = 58˚
4.	a = 20, b = 25, c= 22
5.	<B = 10˚, <C = 100˚ , c = 115

raden · Answer

(1). use the law of sines to  get the measure of angle B
asin(B) = bsin(A)
sin(B) = bsin(A)/a
sin(B) = 15 sin(110)/28
sin(B) = ....
then take arc(sin) to get the measure of angle B
(dont forget use the calculator)

anonymous · Answer

Alright, thank you!

raden · Answer

but that's not clear yet, you need the measure of angle C, and then determine the length of c

raden · Answer

after you get <B, to get <C use the property of the sum of interior angles in a triangle is 180 degrees.
A+B+C = 180
so, C = 180 - (A+B)

raden · Answer

and to get the length of side c, you can use the law of sines or the law of cosines.

raden · Answer

c^2 = (a^2 + b^2 - 2 ab cos(C)
solve for c