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Give a parameter interval that traces the curve exactly once. x = 3sin(2t) y = 1.5cos(t)
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Yo @jim_thompson5910 buddy can you help me out here a bit? :D
Start by letting \(t=0\).
Find the initial position on the interval.
you get \((x,y)=(0,1.5)\)
Now we need to find solutions:\[ 0 = 3\sin(2t),\quad 1.5=1.5\cos(t) \]
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Solutions for the first equation are: \[ \frac \pi 2 n \]And solutions for the second one are: \[ 2\pi n \]
The least common multiple is \(2\pi\) so I'd say that is the period.
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