Mathematics
12 Online
OpenStudy (yamyam70):
How would you verify this ?
cosx
______________ = sec x + tan x
1 - sin x
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OpenStudy (linknissan):
expand secx and tanx
OpenStudy (yamyam70):
1 sin x
_____ + _________
cos x cos x
OpenStudy (yamyam70):
1 + sin x
__________
cos x
OpenStudy (yamyam70):
then what?
ganeshie8 (ganeshie8):
on left hand side, you're seeing 1-sinx in bottom,
so multiply & divide 1-sinx
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ganeshie8 (ganeshie8):
1 + sin x 1-sin x
__________ x ----------
cos x 1-sin x
OpenStudy (yamyam70):
Hmm..
why did you multiply the left side with the result of the right hand side,
is that possible?
ganeshie8 (ganeshie8):
i have just multiplued wat u have wid \(1\)
1-sin x
---------- = \(1\)
1-sin x
ganeshie8 (ganeshie8):
u have this
1 + sin x
__________
cos x
ganeshie8 (ganeshie8):
multiply it 1,
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ganeshie8 (ganeshie8):
1 + sin x
__________ x \(1\)
cos x
OpenStudy (yamyam70):
is this rationalizing?
ganeshie8 (ganeshie8):
1 + sin x 1-sin x
__________ x ----------
cos x 1-sin x
OpenStudy (yamyam70):
please go on
ganeshie8 (ganeshie8):
kindof, but there are no rationals involved here :) its all trig
simplify now
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ganeshie8 (ganeshie8):
use this : \((a+b)(a-b) = a^2-b^2\)
OpenStudy (yamyam70):
I see :)
ganeshie8 (ganeshie8):
1 + sin x 1-sin x
__________ x ----------
cos x 1-sin x
(1-sin^2x)
----------
cos x (1- sinx)
OpenStudy (yamyam70):
and then we use the phytagorean identity ?
ganeshie8 (ganeshie8):
rest is bit easy :)
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ganeshie8 (ganeshie8):
yeah
OpenStudy (yamyam70):
Thanks :)
ganeshie8 (ganeshie8):
u cud have solved this by taking left hand side also
ganeshie8 (ganeshie8):
cosx
______________ = sec x + tan x
1 - sin x
take left hand side,
cosx
______________
1 - sin x
ganeshie8 (ganeshie8):
now multiply & divide it wid \(1\)
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ganeshie8 (ganeshie8):
give it a try when free :)
OpenStudy (yamyam70):
1 + sin x / 1 + sin x ?
ganeshie8 (ganeshie8):
Yes !
OpenStudy (yamyam70):
oh my gosh thanks :)
ganeshie8 (ganeshie8):
np :)
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OpenStudy (yamyam70):
I will close this now, bye :) see you
ganeshie8 (ganeshie8):
seeya :)