Question

3x+3(4-3x)=12-6X

Answer 1

start on the more difficult side of the equation: the left side

3x+3(4-3x)

distribute the 3 which gives you:

3x+12-9x

combine like terms whcih would be the "x" terms:

3x-9x+12=

-6x+12.

Now bring back the right side of the equation:

-6x+12=12-6x.

bring all values to one side of the equation:

-6x+6x+12-12=0

x values cancel as do the +12 and -12 giving you an answer of "0"