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OpenStudy (anonymous):
Need help starting: x^2 - 6x + 9
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OpenStudy (abb0t):
Here, to start, think about this, what TWO numbers
____ \(\sf \color{red}{\times}\) ____ = 9 and ____ \(\sf \color{green}{+}\) ____ = -6
OpenStudy (anonymous):
3 x 3 and 3+3 if I'm not mistaken.
OpenStudy (abb0t):
Yes. Correct.
Now, you have: x\(^2\)\(\sf \color{red}{-3x -3x}\) + 9 = 0
Do you know how to factor? You will be doing that to get groups.
OpenStudy (abb0t):
Factor out into groups. You have p(a + b) - c(a + b) <--- THAT'S how you factor.
OpenStudy (shamil98):
are you looking for the solutions to the quadratic equation or is it for factoring?
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OpenStudy (anonymous):
factoring
OpenStudy (shamil98):
That was rude , abbot, people should state what they need help with.
OpenStudy (abb0t):
Yes, now factor it out @Mason.S
OpenStudy (anonymous):
I agree with shamil. I should have stated that I did need to factor
OpenStudy (abb0t):
Yes. This is how you factor.
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OpenStudy (anonymous):
Well I got it. Thanks for the start help.
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