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evaluate the limit lim X->9 (x-9)/(x^2-81)
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hint : x^2-81 = x^2-9^2
hint2 : a^2-b^2 = (a+b)(a-b)
yea i got that far
good, apply them
i did and i canceled x-9 from the top and bottom and plugged 9+9 but apparently 18 isnt the answer what am i doing wrong
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u did a simple mistake, let me show u :)
\(\large\lim_{ x->9} \frac{(x-9)}{(x^2-81)}\)
\(\large\lim_{ x->9} \frac{(x-9)}{(x+9)(x-9)}\)
\(\large\lim_{ x->9} \frac{\cancel{(x-9)}}{(x+9)\cancel{(x-9)}}\)
\(\large\lim_{ x->9} \frac{1}{(x+9)}\)
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now sub, wat do u get ?
oh i get it thanks so much i was about to go insane
np you're wlcme :)
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