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Precalculus 11 Online
OpenStudy (anonymous):

give the horizontal asymptote h(x)= 9x^3-7x-8/ 4x^4+2

OpenStudy (anonymous):

You plug in whatever would make the bottom zero. That's how you find the asymptote. Whatever makes the bottom half zero. Which in this case would be..... I'm not completely sure haha, but that's how you find it. Or you can graph it on a graphing calculator and just look at it.

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