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OpenStudy (anonymous):
solve the inequality for x
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OpenStudy (anonymous):
\[1<e ^{3x-1}<2\]
OpenStudy (anonymous):
somebody please refresh my memory.
OpenStudy (anonymous):
to remove e, take the natural log of it, or "ln" ln (1) < 3x - 1 < ln (2) I think you can take it from there. :P
OpenStudy (anonymous):
\[0<3x-1<\ln2\] \[x >\frac{ \ln2 +1 }{ 3 }\] ?
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