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Mathematics 19 Online
OpenStudy (anonymous):

solve the inequality for x

OpenStudy (anonymous):

\[1<e ^{3x-1}<2\]

OpenStudy (anonymous):

somebody please refresh my memory.

OpenStudy (anonymous):

to remove e, take the natural log of it, or "ln" ln (1) < 3x - 1 < ln (2) I think you can take it from there. :P

OpenStudy (anonymous):

\[0<3x-1<\ln2\] \[x >\frac{ \ln2 +1 }{ 3 }\] ?

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