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Factor first, then simplify the factors: 2(x+4)(2x-1)^3 + 6(x+4)^2 (2x-1)^2
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\[2(x+4)(2x-1)^3 + 6(x+4)^2(2x-1)^2 \]
How do I begin?
Notice that there are 2 (x+4) term and 2 (2x-1) terms
Or, if you REALLY need the solution, here it is. (WARNING: MAY NOT BE ACCURATE.) 2(x+4)(2x-1)^3 + 6(x+4)^2 (2x-1)^2 =2(x+4)(2x-1)^2((2x-1)+3(x+4)) =2(x+4)(2x-1)(2x-1+3x+12) =2(x+4)(2x-1)(5x-11) There you have it.
find HCF of 2 &6. take the two factors (2x-1) and (x+4) along with their smallest power respectively.
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