Question

Given that a function is of degree 3 and has zeros at -4, -1, and 2, using a = 1, find the equation of the function. which one should i pick?
f(x) = x^3 + 3x^2 – 6x – 8
f(x) = x^3 – 5x^2 – 6x – 8
f(x) = x^3 + 3x^2 – 2x – 8
f(x) = x^3 + 3x^2 – 6x – 8

Answer 1

(x+4)(x+1)(x-2)
(x+4)(x^2-2x+x-2)
(x+4)(x^2-x-2)
(x^3-x^2-2x+4x^2-4x-8)
x^3+3x^2-6x-8

so f(x)=x^3+3x^2-6x-8

Answer 2

thank you

Answer 3

Anytime.