Question

solve the system using elimination
{ 2x+6y=-12
{ 5x-5y=10
A. (2,1)
B. (0,-2)
C. (-2,0)
D (1,2)

Answer 1

2x+6y=-12--------(1
5x-5y=10--------(2

multiplying (1 by 5 and (2 by 6 and adding them we find

10x+30y=-60--------(1
30x-30y=60---------(2
----------------------
40x=0
x=0/40
x=0
Now substituting x=0 in eq (1 we find
2*0+6y=-12
0+6y=-12
6y=-12
y=-12/6
y=-2
{x,y}={0, -2}

Thus option B. (0,-2) is correct Ans.

Answer 2

thank you :) that really helps alot