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OpenStudy (anonymous):
what are the zeros of the function of x^3-4x? how to you solve this?
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OpenStudy (anonymous):
try to factor our an x. you get x(x^2 -4). this can be factored further into x(x-2)(x+2). to find the zeros. try to set each of the "groups" =0 x=0 x-2=0 x+2=0 solve ... i didn't put the answer as i think it is apparent now
OpenStudy (anonymous):
thanks
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