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Determine the interval on which the function is continuous: f(x) = {3x^2 - x - 2, x can't equal 1 {0, x = 1
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@zepdrix
@loser66 is good with these type of problems. It appears that at x=1, f(x) = 0. So, typically in a situation where there is a "whole" in the domain like this, there is a potential for there to be a discontinuity. However, in this case, it appears that f(x) is continuous for all real numbers. @loser66, do you agree?
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