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Find the 11th term in the geometric sequence
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find the 11th term in The geometric sequence in which \[a _{3}\] is 24 and \[a _{5}\] is 96
@ganeshie8
there are two ways to solve this, first method involves finding the common difference and first term
\(\large a_3 = a r^2 = 24\) \(\large a_5 = a r^4 = 96\)
can u solve those two equations and find a, r values ?
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no...
ok let me show u how to solve, take \(\large \frac{a_5}{a_3} \) \(\large \frac{ar^4}{ar^2} = \frac{96}{24}\) \(\large \frac{\cancel{a}r^4}{\cancel{a}r^2} = 4\) \(\large r^2 = 4\) \(\large r = ?\)
once you have r, find a also then use the nth term formula for geometric sequence
try...
r=2?
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@ganeshie8
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