Question

Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°

Answer 1

Look at the picture :
Use from Sin or Cos ?
Can u answer ?
I think @UditKulka can help well :)

Answer 2

The area of a parallelogram is the length of its base multiplied by its height.

Since the smaller angle is 60 degrees, sin(60) is the ratio between the height and the smaller side 6.

Therefore the height is 6sin(60) = 3*sqrt(3).

=> the area is 12*3*sqrt(3) = 36sqrt(3) [b].

Answer 3

@UditKulka thanks that was super helpful

Answer 4

@UditKulka:Realy right :)

Answer 5

thank you!