Question

j

Answer 1

Is the expression:

\(5-\dfrac{3x}{5}\) (which is what you have written)

or is it

\(\dfrac{5-3x}{5}\)

(which, for future reference, you can convey correctly by using ( )'s:
(5-3x)/5

and you'll get better, quicker help. :)

Answer 2

Just use the "reverse" of addition/subtraction with an LCD:

\(\dfrac{a-b}{c}=\dfrac{a}{c}-\dfrac{b}{c}\)

Break it up into a difference of 2 terms, and simplify.

Answer 3

OH thnk you