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OpenStudy (anonymous):
Can someone please help me understand how to solve this? T_T
(3x/5-7)+7
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OpenStudy (yamyam70):
are we solving for x ?
OpenStudy (anonymous):
no it's asking what is equal to it.
OpenStudy (yamyam70):
can you post the complete problem?
OpenStudy (anonymous):
which of the following id equal to (3x/5-7)+7.
a. 5x/3
b. 3x/5
c. (3x-7)+35
d. 3x-35/5
OpenStudy (anonymous):
that T_T
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OpenStudy (yamyam70):
what do you mean by id ?
OpenStudy (anonymous):
*is
OpenStudy (anonymous):
typo
OpenStudy (yamyam70):
I see
OpenStudy (anonymous):
i just have no clue how to solve this T_T
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OpenStudy (yamyam70):
Okay , here goes.
Operate whats inside the parenthesis first
OpenStudy (anonymous):
so would that be 3/5-7?
OpenStudy (yamyam70):
yes :)
OpenStudy (anonymous):
i think i just solved it o.0
OpenStudy (anonymous):
would it be 3x/5
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OpenStudy (yamyam70):
don't forget the x
OpenStudy (yamyam70):
wait a moment
OpenStudy (anonymous):
i did 2/5-7 which got me -6.4 but when added to 7 got me 0.6 which is 3/5 in a fraction
OpenStudy (yamyam70):
is it 5 - 7 ? or 7 - 5 ?
OpenStudy (anonymous):
it's 2/5-7 so the fraction -7
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OpenStudy (yamyam70):
My answer was , 3x - 7
OpenStudy (anonymous):
that's not one of the choices, the only choice that looks like your is (3x-7)+35
OpenStudy (yamyam70):
let me show you the solution,
OpenStudy (anonymous):
please T_T
OpenStudy (yamyam70):
|dw:1378999754374:dw|
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