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OpenStudy (anonymous):

Can someone please help me understand how to solve this? T_T (3x/5-7)+7

OpenStudy (yamyam70):

are we solving for x ?

OpenStudy (anonymous):

no it's asking what is equal to it.

OpenStudy (yamyam70):

can you post the complete problem?

OpenStudy (anonymous):

which of the following id equal to (3x/5-7)+7. a. 5x/3 b. 3x/5 c. (3x-7)+35 d. 3x-35/5

OpenStudy (anonymous):

that T_T

OpenStudy (yamyam70):

what do you mean by id ?

OpenStudy (anonymous):

*is

OpenStudy (anonymous):

typo

OpenStudy (yamyam70):

I see

OpenStudy (anonymous):

i just have no clue how to solve this T_T

OpenStudy (yamyam70):

Okay , here goes. Operate whats inside the parenthesis first

OpenStudy (anonymous):

so would that be 3/5-7?

OpenStudy (yamyam70):

yes :)

OpenStudy (anonymous):

i think i just solved it o.0

OpenStudy (anonymous):

would it be 3x/5

OpenStudy (yamyam70):

don't forget the x

OpenStudy (yamyam70):

wait a moment

OpenStudy (anonymous):

i did 2/5-7 which got me -6.4 but when added to 7 got me 0.6 which is 3/5 in a fraction

OpenStudy (yamyam70):

is it 5 - 7 ? or 7 - 5 ?

OpenStudy (anonymous):

it's 2/5-7 so the fraction -7

OpenStudy (yamyam70):

My answer was , 3x - 7

OpenStudy (anonymous):

that's not one of the choices, the only choice that looks like your is (3x-7)+35

OpenStudy (yamyam70):

let me show you the solution,

OpenStudy (anonymous):

please T_T

OpenStudy (yamyam70):

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