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find the equation of hyperbola that satisfies the given condition: vertex at (6, 5) conjugate axis along the x axis, asymptoes 5x-6y -30 and 5x + 6y - 30= 0..
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Find the slope of the asymptote.
That is \(c\) I think.
Or \(c^2\)? I can't remember!
c..
after finding c??
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Well \(a^2+b^2=c\)
a and b's not given
Find where the asymptotes meet. That will be the center.
Use that to figure out if it is horizontal or vertical parabola. Then you can find a vertex.
okay okay thanks!!
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