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Precalculus
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given tan theta = -4/3 and cos theta > 0 find sin theta
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tan is negative in second and fourth quadrants cos is positive in first and fourth quadrants taking both conditions into account theta is in fourth quadrant where sine is negative
I was just wondering if someone would be willing to check my work? I ended up with -4/5 and have no clue if it's right but I think I did it correctly... If that makes sense.
tan theta=-4/3 implies sin theta is sin theta =-4/5
that is right
YESSSSSSSS!!! Thank you!!
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