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Joshua is creating a series of rectangles, one inside the other. The length of the first rectangle, Rectangle A, is five inches. Joshua dilates Rectangle A about its center by a scale factor of two to get Rectangle B. He repeats this process using the same scale factor till he gets a rectangle of length 80 inches. How many dilations did Joshua perform including the dilation of Rectangle A? 4 2 8 16
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Okay, so, here we say tha we have a rectangle, and we keep expanding it by a proportion of two. So start with 5. 1)5x2=10 2)10x2=20 3)20x2=40 4)40x2= 80 And that's the answer, 4 times.
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