Question

Evaluate the limit \lim_{ x \rightarrow 0 } \frac {\sin(4x) } {9x }

Answer 1

\[\lim_{ x \rightarrow 0 } \frac {\sin(4x) } {9x }\]
using l'hopital's rule.
\[ \lim_{ x \rightarrow 0 } \frac {4cos(4x) } {9 }= \frac{4}{9}\]