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Differentiate: y= x^(5x)
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lny=5xlnx
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take log both sides log y = 5x logx differntiate 1/y * dy = 5x*1/x + 5*logx
okay thanks
1/y * dy = 5x*1/x * dx + 5*logx*dx dy/y=(5+5logx)*dx dy/dx=y*(5+5logx)
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but y=x^5x dy/dx=x^5x*(5+5logx)
okay, yeah I got it, I factored out a 5
okkk :)
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