(x^2 + 3x - 10) / (6x^2 - 24x) multiplied by (2x^2 - 4x) / (x + 5)
\[(x ^{2}+3x-10)/(6x ^{2}-24x)*(2x ^{2}-4x)/(x+5)\]
Is that what it looks like?
yes
i worked out an answer but want to make sure i understand how to do these problems...
okay do you want to show me?
yes, thanks :)
Okay:)
first step got (x + 5) (x - 2) / 6x (x - 4) multiplied by 2x (x - 2) / (x + 5)
answer (x - 2) (x - 2) / 3 (x - 4)
So your just simplifying the equation?
I think so, the directions just say to complete the problems.
It looks fine to me, Do you think the x-2's can be simplified more?
I wasn't sure.
Okay than I wouldn't worry about it :) Congrats.
thanks :)
would you help with another one?
BR goes to you:) I could spare some more time :P
thanks :) factor 27y^3 - 8x^6
(3y)^3 - 2^3 (x^2)^3 ... but can this be factored as a cube?
a3 + b3 = (a + b)(a2 – ab + b2) a3 – b3 = (a – b)(a2 + ab + b2)
It seems like it should but when I substitute and then check it, it doesn't work out so not sure where I am making a mistake.
Sorry I meant: a^3+b^3=(a+b)(a^2-ab+b^2) a^3-b^3=(a-b)(a^2+ab+b^2) I don't believe it can be factored as a cube.
oh, ok thanks :)
No Problem, Hoped I helped :)
You did :)
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