Question

Solve the equation algebraically
6x^2+7x=3

Answer 1

6x^2+7x-3=0
x^2+7/6x-3/6=0
x^2+7/6x+49/144-49/144-1/2=0
(x+7/12)^2-(49/144+1/2)=0
(x+7/12)^2-121/144=0
(x+7/12)^2=121/144
(x+7/12)=+-(11/12)
x=11/12-7/12=1/3
x=-11/12-7/12=-3/2

Answer 2

How did you get + 49/144??

Answer 3

to make it square you should add and minus b^2/4 to equation, that equation is in this form:
x^2+bx+c=0
it's important that x^2 should not have any coefficient

Answer 4

Got it, thanks!

Answer 5

your welcome