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Precalculus 16 Online
OpenStudy (anonymous):

True or false: y - 3 is a factor of P(y) = 2y^3 - 11y^2 +12y + 9

OpenStudy (anonymous):

USE FACTOR THEOREM

OpenStudy (anonymous):

(x-a) is a factor of polynomial P(x) if P(a)=0

OpenStudy (anonymous):

I got that part, what is next?

OpenStudy (anonymous):

Now, find P(3)

OpenStudy (anonymous):

yes (y-3) is it's factor just divide it by factor 2y^3-11y^2+12y+9=(y-3)(2y^2-5y-3)

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