a machine can toss a golf ball a distance of 120 m on a level playing field when the machine is set to an angle of 30 degrees. How far can the machine toss the ball when it is set to an angle of 45 degrees.

Question

anonymous · Answer

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anonymous · Answer

ok so where do i go from there

anonymous · Answer

$$R=\frac{u^2 \sin(2 \theta)}{g}$$
$$\theta = 30 degrees$$R=120m
$$120=\frac{u^2 \sin(2 *30)}{10}$$
find u.

anonymous · Answer

then find R for 45 degrees  with this u.

anonymous · Answer

ok, so is it 170 m, 98 m , 140 m , 85 m or 150 m? trying to check my answer

anonymous · Answer

what u you got?

anonymous · Answer

98 m?

anonymous · Answer

$$u^2 = \frac{120*10}{\sin 60}$$
$$u^2 = 800\sqrt{3}$$

now theta = 45
$$R=\frac{u^2 \sin(2*45)}{10}$$
substitute value of u^2.
$$R=\frac{800 \sqrt{3} \sin(2*45)}{10}$$

anonymous · Answer

$$R=80\sqrt{3}$$

anonymous · Answer

man i missed that up, so with sig figs.... 140 m?