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Precalculus
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(4x-1)^(1/2) - 1/3(4x-1)^3/2
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if there's a fraction in the exponent, take to the power of the numerator and take the root of the denominator. in the first part of this problem: \[(4x-1)^{\frac{ 1 }{ 2 }}=\sqrt{(4x-1)^{1}}\]
would i do that for both parts? or do i also have to distribute the denominator of 3 to all sides
im not too sure what the question is ..
I have to factor completely this equation
sqrt(4x-1)-1/3(4x-1)(sqrt(4x-1)=sqrt(4x-1)(1-4/3x+1) =sqrt(4x-1)(-4/3x+2)
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the greatest common factor is the: ^(1/2)
for example: a - 4a^2 b, the gcf is a a(1-4ab)
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