Question

help see below

Answer 1

solve the quadratic equation for the indicated variable
\[x^2-mx=1 \] for x

Answer 2

\[
\Large x^2-mx-1=0\\

\Large x=\frac{-b\mp\sqrt{b^2-4ac}}{2a}\\
\text{where } a=1\\b=-m\\c=-1



\]

Answer 3

oh ok that makes sense :)
so
\[x=\pm \frac{ \sqrt{m^2+4} }{ 2 }\]

Answer 4

@cinar

Answer 5

\[ \Large x=\frac{ m\mp\sqrt{m^2+4} }{ 2 }\]