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Mathematics 15 Online
OpenStudy (katherinesmith):

Find the number of permutations of the word “helicopter”.

OpenStudy (katherinesmith):

i figured it out, 10!/2!

OpenStudy (anonymous):

HELICOPTER -10 letters - E repeats 2 times - every other letter repeats only once - helicopter = 9 distinct letters - total of 10 letters Number of permutations without replacement for distant objects (T)! / X!, where T is the total number of letters to be permuted, and X is the objects that are similar There are 10 total letters - so T = 10. - There are 2 objects that are similar (E), so X = 2 Permutations of HELICOPTER = 10! / 2!

OpenStudy (anonymous):

\[\frac{ (total~number~of~letters)! }{ (repeated~letters)! } = \frac{ 10! }{ 2! }\]

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