Question

C++, 2 dimensional arrays !


Please tell me how to do the (c) and (b) part of this so that I can get started. I am really new to this concept! Any help appreciated ! http://screencast.com/t/NVx3zNWGTGdb

Answer 1

for(i=0;i<n;i++)
for(j=0;j<n;j++)
AR[i]=AR[i]*AR[j]
given some hints..think about it now

Answer 2

```
for(i=0;i<n;i++)
for(j=0;j<n;j++)
AR[i]=AR[i]*AR[j] //Huh?
```
Because it requires a 2d array, it will be declared it as:
`int Table[10][10]`

However, the nested loops is a part of the solution to this.
```
for(int i = 0; i<table_columns; i++)
{
for(int j = 0; j<table_rows; j++)
{
// do something with Table[?][?]
}
}
```

Answer 3

I already went that far, please, can you help me a bit more ? Like a silght step further

Answer 4

my code so far: http://pastebin.com/buYqWLV3 @e.mccormick @DLS

Answer 5

sry the site is blocked here :( can't help

Answer 6

My updated code : http://pastebin.com/LC1iLdxL

Answer 7

There seems to be a } in the wrong place.
Also, I am not sure why you are using so man variables, especially in the global scope.... i, j, o, u? I think yo could do it with just i and j.

Also, this is a miltiplication table. I see some addition going on, but no multiplication.

If you look at a Row i \(\times\) Column j form, it is like this:

\(\begin{array}{|c|c|} \hline
\, & \, & A[i][0] & A[i][1] & A[i][2] & A[i][3] \\ \hline
\, & \,& 1 & 2 & 3 & 4 \\ \hline
A[0][j] & 1 & 1\cdot 1 & 1\cdot 2 & 1\cdot 3 &1\cdot 4\\ \hline
A[1][j] & 2 & 2\cdot 1 & 2\cdot 2 & 2\cdot 3 & 2\cdot 4 \\ \hline
A[2][j] & 3 & 3\cdot 1 & 3\cdot 2 & 3\cdot 3 & 3 \cdot 4 \\ \hline
A[3][j] & 4 & 4\cdot 1 & 4\cdot 2& 4\cdot 3 & 4 \cdot 4 \\ \hline
\end{array}\)

Note that the i and i of the A[i][j] position is one less for both i and j than what needs to be miltiplied! So A[0][0] is NOT \(0\cdot 0\) but is actually \(1\cdot 1=1\). Similarly, \(A[5][7] = (5+1)(7+1)=48\)