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OpenStudy (anonymous):
The triangles are congruent.Find the length of each hypotenuse.(HELP I FORGOT HOW TO DO THIS)
A.3
B.5
C.17
D.22
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OpenStudy (anonymous):
OpenStudy (cggurumanjunath):
equate bc =de;
ef=ac.
OpenStudy (cggurumanjunath):
find the values of x and y.
OpenStudy (anonymous):
5x+7=6x+2y like this?
OpenStudy (cggurumanjunath):
s
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OpenStudy (anonymous):
x=7-2y
OpenStudy (cggurumanjunath):
is it clear @HendersonNeedsYurHelp because it is given triangles are congruent so.
OpenStudy (anonymous):
???
OpenStudy (anonymous):
how do i find the values of x and y?
OpenStudy (cggurumanjunath):
ac=ef?
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OpenStudy (anonymous):
y+3=2y+1
OpenStudy (cggurumanjunath):
s
OpenStudy (cggurumanjunath):
find y
OpenStudy (anonymous):
how?
OpenStudy (cggurumanjunath):
y+3=2y+1
find y
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OpenStudy (anonymous):
y=2
OpenStudy (cggurumanjunath):
correct,then what is x
OpenStudy (cggurumanjunath):
x=7-2y
put y=2
and find x
OpenStudy (anonymous):
x=7-2(2)
OpenStudy (cggurumanjunath):
s
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OpenStudy (anonymous):
7-4=3
OpenStudy (cggurumanjunath):
you are right.now find ed.
OpenStudy (anonymous):
ed?
OpenStudy (wolf1728):
y + 3 = 2y + 1
y = 2
OpenStudy (anonymous):
6x+2y
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OpenStudy (cggurumanjunath):
ed=6x+2y
put x=3 and y=2
OpenStudy (cggurumanjunath):
ed is the hypotenuse.
OpenStudy (anonymous):
so my answer is 5?
OpenStudy (cggurumanjunath):
ed=6(3)+2(2)=18+4=22.
OpenStudy (cggurumanjunath):
bc=ed.
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OpenStudy (anonymous):
so the length of the hypotenuse is 5.
OpenStudy (cggurumanjunath):
no it is 22.
OpenStudy (cggurumanjunath):
so the length of the hypotenuse is 5. how ?
OpenStudy (anonymous):
the length of the hypotenuse is 22.
OpenStudy (cggurumanjunath):
s
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OpenStudy (cggurumanjunath):
you got it.
OpenStudy (wolf1728):
5x + 7 = 6 x + 2y
5x + 7 = 6x + 2•2
x = 3
Put x and y into either hypotenuse value
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