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Find the force if water acting on a trapezoidal part of the dam covered by water (upper base of the trapezoid is on the surface). If the trapezoid has height of 50 meters, lower base is 20m, uppberbase is 10m.
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This confuses me because, the dam is upside down. In class, I was taught how to do it rightside up: |dw:1379282215071:dw|
I know the formulas needed: \[F=P*A\] & \[P=(density)*(gravity)*(distance \to the surface)\] & \[F=\int\limits_{e}^{h} (density)*g*x*w(x)dx\] where w(x) is the width of the down & density is 1000 kg/m^3
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