Question

tan^2xsin^2x=tanx-sin^2x

Answer 1

I'm pretty sure that's supposed to be tan^2x-sin^2x on the RHS

Try using the Fundamental Identity on the LHS, to replace sin^2x.... then multiply it out and see what falls into place. :)

Answer 2

Fundamental ID: \(\Large \sin^2x+\cos^2x=1\)

rearrange it to solve it for \(\sin^2x\), then use that on the LHS.

Answer 3

Oh okay, this helps me a lot. Thanks (:

Answer 4

You're welcome. :)