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Equation ... Pls solve . N explain. x(4x-3)=(2x-1)^2.
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x(4x-3) = (2x-1)^2 => 4x^2-3x = 4x^2-4x+1 => 4x^2-4x^2 =3x-4x+1 => 0 = -x+1 => x=1
Distribute the x inside the (). 4x^2-3x Square (2x-1) using FOIL. 4x^2-6x+1 4x^2-3x = 4x^2 - 6x +1 4x^2 cancels from both sides -3x = -6x + 1 3x = 1 x = 1/3
your foil should be 4x^2-4x+1
You're right. I should stop I've been sitting here too long
haha no you're fine
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