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If y= sin2 2x, find dy/dx
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two of many options:\[\sin^2 (2x) = (\sin(2x))^2\] or \[\sin^2(2x) = \frac{ 1 - \cos(4x) }{ 2 }\]
thank you.
Find the first derivative:Y=sin(4x-5)
4cos(4x-5)
y'=2*2sin^2(2x)=4sin^2(2x)
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Evaluate the limit: lim(-15) x 3
What is the minium value of thefunction F defined by F(x)=x2-6x+8
Help me...How high is a semi-elliptical arch of height 20ft and span 80 ft. at a distamce of 15 ft from the end.
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