Question

\[\int\limits \frac{ 3v-2 }{ 1+4v-3v^{2} }dv=\int\limits x dx\]

Answer 1

Is there a question?

Answer 2

for left hand integral, you can just substitute
u= 1+4v-3v^2

then du= ... ?

Answer 3

I don't understand the right hand side of the equation... but okay, sure. Substitute that for u, then what would du be?