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Mathematics 16 Online
OpenStudy (anonymous):

sec^2(x)-2secx+0

OpenStudy (jdoe0001):

hmm... are you supposed to find "x"?

OpenStudy (anonymous):

sorry it was sec^2(x)-secx=0

OpenStudy (anonymous):

and yes to finding (x)

OpenStudy (jdoe0001):

so... find "x"? well, notice \(\bf sec^2(x)-secx=0 \\\quad \\ \textit{taking common factor}\\ sec^2(x)-secx=0 \implies sec(x)[sec(x)-1]=0\)

OpenStudy (anonymous):

Thank you!!

OpenStudy (jdoe0001):

yw

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