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OpenStudy (anonymous):
sec^2(x)-2secx+0
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OpenStudy (jdoe0001):
hmm... are you supposed to find "x"?
OpenStudy (anonymous):
sorry it was sec^2(x)-secx=0
OpenStudy (anonymous):
and yes to finding (x)
OpenStudy (jdoe0001):
so... find "x"? well, notice \(\bf sec^2(x)-secx=0 \\\quad \\ \textit{taking common factor}\\ sec^2(x)-secx=0 \implies sec(x)[sec(x)-1]=0\)
OpenStudy (anonymous):
Thank you!!
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OpenStudy (jdoe0001):
yw
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