Question

Need help! (Algebra 1)...

Answer 1

?

Answer 2

area=bh/2=47
b=x and h=x

Answer 3

a=1/2 base*height
47=1/2*x*x
94=x^2
x=\[\sqrt{94}\]
9.7

Answer 4

ok first The Area of a triangle is A= \[\frac{ 1 }{ 2 }*B*H\]

Therefore \[47=\frac{ 1 }{ 2 }*X ^{2}\]

Solve by Multiplying both sides by 2\[47*2=\frac{ 1 }{2 } X ^{2}*2\]
\[94=X ^{2}\]
Now solve for the square root \[\sqrt{94}=\sqrt{X ^{2}}\]
\[X=9.7\]

Answer 5

can you guys help me with this one?

Answer 6

@kola908 thanks good explanation!

Answer 7

you must consider the y intercept of the graph, the y intercept of the given graph is -1, a number which is lower than -1 is -3

Answer 8

so im correct right?

Answer 9

yes