Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the value of acceleration of the box?

A)0.7 meters/second
B)2.6 meters/second
C)3.2 meters/second
D)3.6 meters/second

Question

Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the value of acceleration of the box?

A)0.7 meters/second
B)2.6 meters/second
C)3.2 meters/second
D)3.6 meters/second

***[isuru]*** · Answer

|dw:1379364717766:dw|

Hi,

  resultant force = applied force - friction
                        = 25N - 2.6N
                        = 22.4N
According to Newton's second law
               F = ma
            22.4N = 7 Kg*a
                   a = 22.4/7
                      = 3.2 m/s^2
So the choice is C