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4cos^2(x) +4cosx=-1
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you want to solve for x or what?
Yes
well using a simple substitution, let cos(x) = u so we have 4u^2+4u -1 = 0 and then using the quadratic formula ( i wont write this part because its too long) but you get u = 1/2 ====> cos(x) = 1/2 ===> cos^-1(1/2) = x so x = plus-or-minus π/3
Thank you I really appreciate all your help
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